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Julien Lopez authored
At this point, the lexer gives a type if it sees a "'" then IDENT then ' '. This is not enough, but now simple tests like this one works: fun ('A -> Int) _ -> 0
162b4367
At this point, the lexer gives a type if it sees a "'" then IDENT then ' '. This is not enough, but now simple tests like this one works: fun ('A -> Int) _ -> 0